RATING CHARACTERISTIC CURVES ( 2SA1036KGP )
Fig.4 Collector-emitter saturation
voltage vs. collector current
Fig.5 Collector-emitter saturation
voltage vs. collector current
Fig.6 DC current gain vs.
collector current
-1
-1
1000
500
Ta=
25OC
Ta=25OC
lC/lB=10
-0.5
-0.5
200
100
50
-0.2
-0.1
-0.2
-0.1
lC
/l
B
=
50
Ta
=
100OC
25OC
-55OC
20
10
-0.05
-0.05
20
10
-0.02
-0.5 -1 -2
-0.02
-0.5 -1 -2
-0.1
-0.5 -1.0
-5 -10
-50 -100
-1000
-5 -10
-50 -100
-500
-5 -10
-50 -100
-500
COLLECTOR CURRENT : I
C(mA)
COLLECTOR CURRENT : I (mA)
C
COLLECTOR CURRENT : I (mA)
C
Fig.8 Gain bandwidth product
vs. emitter current
Fig.7 DC current gain vs.
collector current
Fig.9 Collector output capacitance vs.
collector-base voltage
Emitter input capacitance vs.
emitter-base voltage
100
1000
500
Ta 25OC
=
V
CE=
-3V
Ta 25OC
=
VCE -5V
=
f
I
I
1MHz
=
1000
500
E
0A
0A
=
50
20
C
=
200
100
50
200
100
10
5
50
20
10
2
-0.5
-0.1
-0.5 -1
-5 -10
-50 -100
-1000
0.5
1
2
5
10
20
50
-1
-2
-5
-10
-20
-50
V)
EMITTER CURRENT : IE mA)
COLLECTOR CURRENT : I
C(
mA)
COLLECTOR TO BASE VOLTAGE : VCB
EMITTER TO BASE VOLTAGE : VEB
(
(
(
V)