EUP9232
TEST Circuits
(1) Test Condition 1, Test Circuit 1
Set S1=OFF, V1= V2 =3.6 V, and V3= 0 V under
normal condition. Increase V1 from 3.6V gradually. The
V1 voltage when CO = “L” is overcharge detection
voltage 1 (V
CU1
). Decrease V1 gradually. The V1
voltage when CO = “H” is overcharge release voltage
1(V
CD1
). Further decrease V1. The V1 voltage when
DO= “L” is overdischarge voltage 1(V
DD1
). Increase V1
gradually. The V1 voltage when DO = “H” is
overdischarge release voltage 1 (V
DU1
). Set S1 = ON,
and V1= V2= 3.6 V and V3 = 0 V under normal
condition. Increase V1 from 3.6V gradually. The V1
voltage when CO = “L” is auxiliary overcharge detection
voltage 1 (V
CUaux1
).
(2) Test Condition 2, Test Circuit 1
Set S1=OFF, V1= V2 =3.6 V, and V3= 0V under normal
condition. Increase V2 from 3.6V gradually. The V2
voltage when CO = “L” is overcharge detection voltage
2 (V
CU2
). Decrease V2 gradually. The V2 voltage when
CO = “H” is overcharge release voltage 2(V
CD2
). Further
decrease V2. The V2 voltage when DO= “L” is
overdischarge voltage 2(V
DD2
). Increase V2 gradually.
The V2 voltage when DO = “H” is overdischarge release
voltage 2 (V
DU2
). Set S1 = ON, and V1= V2= 3.6 V and
V3 = 0 V under normal condition. Increase V2 from 3.6V
gradually. The V2 voltage when CO = “L” is auxiliary
overcharge detection voltage 2 (V
CUaux2
).
(3) Test Condition 3, Test Circuit 1
Set S1=OFF, V1 =V2 =3.6 V, and V3 = 0V under
normal condition. Increase V3 from 0V gradually. The
V3 voltage when DO= “L” is overcurrent detection
voltage 1 (V
IOV1
). Set S1 =ON, V1=V2= 3.6V, V3=0
under normal condition. Increase V3 from 0 V
gradually.V3 voltage when DO= “L” is overcurrent
detection voltage 2 (V
IOV2
).
(4) Test Condition 4, Test Circuit 2
Set S1 = ON, V1 = V2 =3.6V, and V3 =0 V under
normal condition and measure current consumption.
Current consumption I1 is the normal condition current
consumption (I
OPE
). Set S1 =OFF, V1 =V2 =1.5V under
overdischarge condition and measure current
consumption. Current consumption I1 is the
power-down current consumption (I
PDN
).
(5) Test Condition 5, Test Circuit 2
Set S1 =ON, V1=V2 = 1.5 V, and V3 =0 V under
overdischarge condition. (V1+V2)/I2 is the internal
resistance between VCC and VM (Rvcm).
Set S1= ON, V1=V2=3.5V, and V3 = 1.0 V under
overcurrent condition. V3 / I2 is the internal resistance
between VSS and VM (Rvsm).
DS9232 Ver1.1
Feb. 2007
(6) Test Condition 6, Test Circuit 3
Set S1=ON, S2=OFF,V1=V2=3.6V, and V3 =0 V
under normal condition. Increase V4 from 0V gradually.
The V4 voltage when I1=10µA is DO voltage “H” (V
DOH
).
Set S1=OFF, S2=ON,V1=V2=3.6V, and V3=0.5 V
under overcurrent condition. Increase V5 from 0V
gradually. The V5 voltage when I2=10µA is DO voltage
“L” (V
DOL
).
(7) Test Condition 7, Test Circuit 4
Set S1 = ON, S2=OFF, V1=V2 =3.6V, and V3 =0 V
under normal condition. Increase V4 from 0V gradually.
The V4 voltage when I1=10µA is the CO “H” voltage
(V
COH
).
Set S1=OFF, S2=ON,V1=4.4, V2 =3.6V, and V3 =0 V
under overcharge condition. Increase V4 from 0V
gradually. The V5 voltage when I1=10µA is CO voltage
“L” (V
COL
).
(8) Test Condition 8, Test Circuit 5
Set V1=V2=3.6V and V3=0V under normal condition.
Increase V1 from (V
CU1
-0.2V) to (V
CU1
+0.2V)
immediately (within 10µs). The time after V1 becomes
(V
CU1
+0.2V) until CO goes “L” is the overcharge
detection delay time 1 (t
CU1
).
Set V1=V2=3.5V and V3=0V under normal condition.
Decrease V1 from (V
DD1
+0.2V) to (V
DD1
-0.2V)
immediately (within 10µs). The time after V1 becomes
(V
DD1
-0.2V) until DO goes “L” is the overcharge
detection delay time 1 (t
DD1
).
(9) Test Condition 9, Test Circuit 5
Set V1=V2=3.6V and V3=0V under normal condition.
Increase V2 from (V
CU2
-0.2V) to (V
CU2
+0.2V)
immediately (within 10µs). The time after V2 becomes
(V
CU2
+0.2V) until CO goes “L” is the overcharge
detection delay time 2 (t
CU2
).
Set V1=V2=3.6V and V3=0V under normal condition.
Decrease V2 from (V
DD2
+0.2V) to (V
DD2
-0.2V)
immediately (within 10µs). The time after V2 becomes
(V
DD2
-0.2V) until DO goes “L” is the overcharge
detection delay time 2 (t
DD2
).
(10) Test Condition 10, Test Circuit 5
Set V1=V2=3.6V and V3=0V under normal condition.
Increase V3 from 0V to 0.5V immediately(within 10µs).
The time after V3 becomes 0.5V until DO goes “L” is
the overcurrent detection delay time 1(t
I0V1
).
(11) Test Condition 11, Test Circuit 6
Set V1=V2=0V and V3=2V,and decrease V3 gradually.
The V3 voltage when CO=”L”(V
CC
-0.3V or lower) is the
0V charge starting voltage (V
0CHA
).
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EUTECH [ EUTECH MICROELECTRONICS INC ]
