LT1249
U
W U U
APPLICATIONS INFORMATION
LINE
MAIN INDUCTOR
The Figure 3 circuit therefore has 382V on VOUT, and an
overvoltage level = (VOUT + 44V), or 426V. With a 22µA
hysteresis, VOUT then has to drop 22V to 404V before
feedback recovers and the switch turns back on.
N
N
P
S
R1
90k
1W
D1
D3
V
CC
+
+
C1
M
OUT is a high impedance current output. In the current
2µF
+
+
C3
390µF
C4
56µF
loop, offset line current is determined by multiplier offset
current and input offset voltage of the current amplifier.
A negative 4mV current amplifier VOS translates into
20mA line current and 5W input power for 250V line if
0.2Ω sense resistor is used. Under no load or when the
loadpowerislessthanthisoffsetinputpower, VOUT would
slowly charge up to an overvoltage state because the
overvoltage comparator can only reduce multiplier output
current to zero. This does not guarantee zero output
currentifthecurrentamplifierhasoffset.Toregulate VOUT
under this condition, the amplifier M1 (see Block Dia-
gram), becomes active in the current loop when VAOUT
goes down to 1V. The M1 can put out up to 15µA to the 4k
resistor at the inverting input to cancel the current ampli-
fier negative VOS and keep VOUT error to within 2V.
D2
C2
2µF
1249 F04
ALL CAPACITORS ARE RATED 35V
Figure 4. Power Supply for LT1249
C2
1000pF
450V
MAIN INDUCTOR
LINE
R1
90k
1W
D2
D1
D3
V
CC
+
C3
390µF
35V
C4
+
18V
56µF
35V
1249 F05
Undervoltage Lockout
Figure 5. Power Supply for LT1249
The LT1249 turns on when VCC is higher than 16V and
remains on until VCC falls below 10V, whereupon the chip
enters the lockout state. In the lockout state, the LT1249
only draws 250µA, the oscillator is off, the VREF and the
GTDR pins remain low to keep the power MOSFET off.
auxiliary winding determines VCC according to: VOUT/(VCC
– 2V) = NP/NS. For 382V VOUT and 18V VCC, NP/NS ≈ 19.
In Figure 5 a new technique for supply voltage eliminates
the need for an extra inductor winding. It uses capacitor
charge transfer to generate a constant current source
which feeds a Zener diode. Current to the Zener is equal to
(VOUT – VZ)(C)(f), where VZ is Zener voltage and f is
switching frequency. For VOUT = 382V, VZ = 18V, C =
1000pF and f = 100kHz, Zener current will be 36mA. This
is enough to operate the LT1249, including the FET gate
drive.
Start-Up and Supply Voltage
The LT1249 draws only 250µA before the chip starts at
16V on VCC. To trickle start, a 90k resistor from the power
linetoVCC suppliesthetricklecurrentandC4holdstheVCC
up while switching starts (see Figure 4). Then the auxiliary
winding takes over and supplies the operating current.
Note that D3 and the large value C3, in both Figures 4 and
5, are only necessary for systems that have sudden large
load variation down to minimum load and/or very light
load conditions. Under these conditions, the loop may
exhibitastart/restartmodebecauseswitchingremainsoff
long enough for C4 to discharge below 10V. The C3 will
hold VCC up until switching resumes. For less severe load
variations, D3 is replaced with a short and C3 is omitted.
The turns ratio between the primary winding and the
Output Capacitor
The peak-to-peak 120Hz output ripple is determined by:
V
P-P = (2)(ILOADDC)(Z)
where ILOADDC: DC load current
Z: capacitor impedance at 120Hz
For 180µF at 300W load, ILOADDC = 300W/385V = 0.78A,
8