HIGH RIPPLE-REJECTION AND SMALL PACKAGE CMOS VOLTAGE REGULATOR
S-1323 Series
Rev.4.2_00
Electrical Characteristics
Table 5
(Ta = 25°C unless otherwise specified)
Test
Item
Symbol
VOUT(E)
Conditions
Min.
Typ.
Max.
Unit
Circuit
VOUT(S) VOUT(S) VOUT(S)
Output voltage*1
V
IN = VOUT(S) + 1.0 V, IOUT = 30 mA
V
1
× 0.99
150*5
× 1.01
0.65
Output current*2
IOUT
Vdrop
VIN ≥ VOUT(S) + 1.0 V
OUT = 150 mA
OUT(S) + 0.5 V ≤ VIN ≤ 6.5 V,
OUT = 30 mA
0.50
mA
V
3
1
Dropout voltage*3
I
V
I
∆VOUT1
∆VIN•VOUT
Line regulation
Load regulation
0.02
0.1
40
% / V
1
1
1
2
V
IN = VOUT(S) + 1.0 V,
1.0 mA ≤ IOUT ≤ 150 mA
IN = VOUT(S) + 1.0 V, IOUT = 30 mA,
−40°C ≤ Ta ≤ 85°C
∆VOUT2
20
mV
∆VOUT
∆Ta•VOUT
Output voltage
V
ppm/
°C
100
70
temperature coefficient*4
Current consumption
during operation
Current consumption
during shutdown
Input voltage
V
IN = VOUT(S) + 1.0 V, ON/OFF pin = ON,
no load
IN = VOUT(S) + 1.0 V, ON/OFF pin = OFF,
no load
ISS1
90
µA
V
ISS2
VIN
0.1
1.0
6.5
µA
V
2
4
2.0
1.5
Shutdown pin
input voltage “H”
Shutdown pin
input voltage “L”
Shutdown pin
input current “H”
Shutdown pin
input current “L”
VSH
V
V
V
IN = VOUT(S) + 1.0 V, RL = 1.0 kΩ
V
VSL
ISH
IN = VOUT(S) + 1.0 V, RL = 1.0 kΩ
IN = 6.5 V, VON/OFF = 6.5 V
−0.1
−0.1
0.3
0.1
0.1
V
4
4
4
5
3
µA
µA
dB
mA
ISL
VIN = 6.5 V, VON/OFF = 0 V
V
IN = VOUT(S) + 1.0 V, f = 1.0 kHz,
RR
Ripple rejection
70
250
∆Vrip = 0.5 Vrms, IOUT = 30 mA
V
IN = VOUT(S) + 1.0 V, ON/OFF pin = ON,
Short-circuit current
Ishort
V
OUT = 0 V
*1. VOUT(S): Specified output voltage
VOUT(E): Actual output voltage at the fixed load
The output voltage when fixing IOUT(= 30 mA) and inputting VOUT(S) + 1.0 V
*2. The output current at which the output voltage becomes 95% of VOUT(E) after gradually increasing the output current.
*3. Vdrop = VIN1 − (VOUT3 × 0.98)
VOUT3 is the output voltage when VIN = VOUT(S) + 1.0 V and IOUT = 150 mA.
V
IN1 is the input voltage at which the output voltage becomes 98% of VOUT3 after gradually decreasing the input
voltage.
*4. The change in temperature [mV/°C] is calculated using the following equation.
∆VOUT
∆Ta
∆VOUT
*2
*3
[
mV/°C
]
*1 = VOUT(S)
[
V
]
×
ppm/°C ÷1000
[ ]
∆Ta • VOUT
*1. The change in temperature of the output voltage
*2. Specified output voltage
*3. Output voltage temperature coefficient
*5. The output current can be at least this value.
Due to restrictions on the package power dissipation, this value may not be satisfied. Attention should be paid to the
power dissipation of the package when the output current is large.
This specification is guaranteed by design.
Seiko Instruments Inc.
7