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AAT3215IJS-2.85-T1 参数 Datasheet PDF下载

AAT3215IJS-2.85-T1图片预览
型号: AAT3215IJS-2.85-T1
PDF下载: 下载PDF文件 查看货源
内容描述: 150毫安CMOS高性能LDO [150mA CMOS High Performance LDO]
分类和应用:
文件页数/大小: 18 页 / 343 K
品牌: AAT [ ADVANCED ANALOG TECHNOLOGY, INC. ]
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150mA CMOS High Performance LDO
Thus, the AAT3215 can sustain a constant 2.5V out-
put at a 150mA load current as long as V
IN
is
6.00V
at an ambient temperature of 25°C. 6.0V is the
absolute maximum voltage where an AAT3215
would never be operated, thus at 25°C, the device
would not have any thermal concerns or operational
V
IN(MAX)
limits.
This situation can be different at 85°C. The follow-
ing is an example for an AAT3215 set for a 2.5V
output at 85°C:
Voltage Drop (V)
AAT3215
For a 150mA output current and a 2.7V drop
across the AAT3215 at an ambient temperature of
85°C, the maximum on-time duty cycle for the
device would be 85.54%.
The following family of curves show the safe oper-
ating area for duty-cycled operation from ambient
room temperature to the maximum operating level.
Device Duty Cycle vs. V
DROP
(V
OUT
= 2.5V @ 25°C)
3.5
3
2.5
2
1.5
1
0.5
0
0
10
20
30
40
50
60
70
80
90
100
V
OUT
I
OUT
I
GND
= 2.5V
= 150mA
= 150µA
200mA
V
IN(MAX)
=
211mW + (2.5V
·
150mA)
150mA + 150μA
V
IN(MAX)
= 3.90V
From the discussion above, P
D(MAX)
was deter-
mined to equal 211mW at T
A
= 85°C.
Higher input-to-output voltage differentials can be
obtained with the AAT3215, while maintaining device
functions within the thermal safe operating area. To
accomplish this, the device thermal resistance must
be reduced by increasing the heat sink area or by
operating the LDO regulator in a duty-cycled mode.
For example, an application requires V
IN
= 4.2V
while V
OUT
= 2.5V at a 150mA load and T
A
= 85°C.
V
IN
is greater than 3.90V, which is the maximum
safe continuous input level for V
OUT
= 2.5V at
150mA for T
A
= 85°C. To maintain this high input
voltage and output current level, the LDO regulator
must be operated in a duty-cycled mode. Refer to
the following calculation for duty-cycle operation:
I
GND
= 150µA
I
OUT
= 150mA
V
IN
= 4.2V
V
OUT
= 2.5V
Duty Cycle (%)
Device Duty Cycle vs. V
DROP
(V
OUT
= 2.5V @ 50°C)
3.5
Voltage Drop (V)
3
2.5
2
1.5
1
0.5
0
0
10
20
30
40
50
60
70
80
90
100
200mA
150mA
Duty Cycle (%)
Device Duty Cycle vs. V
DROP
(V
OUT
= 2.5V @ 85°C)
3.5
Voltage Drop (V)
%DC = 100
P
D(MAX)
(V
IN
- V
OUT
)I
OUT
+ (V
IN
·
I
GND
)
3
2.5
2
1.5
1
0.5
0
0
10
20
30
40
50
60
70
80
100mA
211mW
%DC = 100
(4.2V - 2.5V)150mA + (4.2V
·
150μA)
%DC = 85.54%
200mA
150mA
P
D(MAX)
was assumed to be 211mW.
90
100
Duty Cycle (%)
12
3215.2006.05.1.6