R
JCS5N50T
特征曲线
电特性(曲线)
瞬态热响应曲线
对于JCS5N50VT / RT
( t)的热响应
1
D = 0 .5
0 .2
0 .1
N
1
2
3
释:
Z
θ
J·C ( T) = 1 0.3 8
℃
/ W M A X
ð ü TY F A C到R, D = T1 / T2
牛逼J·M -T C = P D M * Z
θ
J·C (T )
0 .1
0 .0 5
0 .0 2
0 .0 1
θ
JC
Z
P
DM
0 .0 1
S IN克乐P ü LS ê
1 E -4
1 E -3
0 .0 1
0 .1
t1
t2
1 E -5
1
10
t
1
S单方W¯¯ AVE P ü LS E D市建局TIO N [秒]
瞬态热响应曲线
对于JCS5N50CT
( t)的热响应
1
D = 0 .5
0 .2
0 .1
N
1
2
3
释:
Z
θ
J·C
(t)= 1 .2 3
℃
/ W M A X
ð ü TY F A C到R, D = T1 / T2
T
J·M
-T
c
= P
D M
* Z
θ
J·C (T )
0 .1
0 .0 5
0 .0 2
0 .0 1
θ
JC
Z
P
DM
0 .0 1
S IN克乐P ü LS ê
1 E -4
1 E -3
0 .0 1
0 .1
t1
t2
1 E -5
1
10
t
1
S单方W¯¯ AVE P ü LS E D市建局TIO N [秒]
瞬态热响应曲线
对于JCS5N50FT
D = 0 .5
( t)的热响应
1
0 .2
0 .1
0 .0 5
N
1
2
3
释:
Z
θ
J·C ( T) = 3 0.0 8
℃
/ W M A X
ð ü TY F A C到R, D = T1 / T2
牛逼J·M -T C = P D M * Z
θ
J·C (T )
0 .1
0 .0 2
0 .0 1
θ
JC
Z
P
DM
S IN克乐P ü LS ê
0 .0 1
1 E -5
1 E -4
1 E -3
0 .0 1
0 .1
t1
t2
1
10
t
1
S单方W¯¯ AVE P ü LS E D市建局TIO N [秒]
版本:201010C
7/12